Calculation For Energy (Atp ) Generated By Fatty Acid Oxidation , Tca Cycle , Glycolysis & Pdh System
I) Basic Rules-
A) Energetics Of Glycolysis-
1. Energy Production Steps-
2nadh2= 2× 2.5 Atp (New) & 2× 3 Atp (Old)= 5 Atp (New) & 6 Atp (Old) - For Aerobic Glycolysis
Substrate Level Phosphorylation = 2× 2atp = 4 Atp
Total= 9 Atp (New) & 10 Atp (Old)-aerobic Glycolysis
= 4 Atp - Anerobic Glycolysis
2. Energy Utilizing Steps-
2× 1atp = 2atp
3. Net Atp Produced-
For Aerobic Glycolysis- 9 Atp (New) & 10 Atp (Old) - 2atp= 7 Atp (New) & 8 Atp (Old)
For Anerobic Glycolysis - 4 Atp - 2atp = 2atp
B) Energetics Of Pyruvate Dehydrogenase Complex-
Energy From Conversion Of 2 Moles Of Pyruvate To Acetyl Coa (Aerobic Respiration) = 2× 1nadh2= 2nadh2
Net Energy Yield= 2nadh2 = 2× 2.5 Atp (New) & 2 × 3 Atp (Old) = 5 Atp (New) & 6 Atp (Old)
C. Energetics Of Tca Cycle-each Cycle With 1acetyl Coa Metabolism Produces-
3nadh2 = 3 × 2.5 Atp (New) & 3×3 Atp (Old) = 7.5 Atp (New) & 9 Atp (Old)
1fadh2 = 1× 1.5 Atp (New) & 1×2 Atp (Old) = 1.5 Atp (New) & 2 Atp (Old)
Substrate Level Phosphorylation- 1 Gtp Formed Which Is Converted To Atp Via Adp
Gtp + Adp = Atp + Gdp
Thus 1atp
Net Yield Of Atp Per Turn ( 1mol Of Acetyl Coa) = 10 Atp (New) & 12 Atp (Old)
Thus Total Atp In Tca Cycle Per Molecule Of Glucose = 2 Acetyl Coa =2× 10/12= 20 Atp (New) & 24 Atp (Old)
D) Thus Net Yield Of Atp When 1molecule Of Glucose Is Completely Oxidised Aerobically-
1. From Aerobic Glycolysis= 7 Atp (New) & 8 Atp (Old)
2. From Pdh Complex= 5 Atp (New) & 6 Atp (Old)
3. From Tca Cycle= 20 Atp (New) & 24 Atp (Old)
Net Atp Produced= 32 Atp (New) & 38 Atp (Old)
E) Energetics Of Fatty Acid Oxidation-
1. Initial Activation Req 2 Atp= (-2atp)
2. Each Cycle Removes 1acetyl Coa & Produces-
1fadh2=1.5 Atp (New) & 2 Atp (Old)
1 Nadh2= 2.5 Atp (New) & 3 Atp (Old)
Total = 4 Atp (New) & 5 Atp (Old)
3. Thus Each Cycle Produces 4 Atp (New) & 5 Atp (Old) & 1 Acetyl Coa
4. Each Mole Of Acetyl Coa Produces 10 Atp (New) & 12 Atp (Old) In Tca Cycle
5. Now Taking Example Of Say Palmitic Acid- (C16) Saturated Fatty Acid
It Undergoes 7 Cycles Of Beta Oxidation To Produce 8 Moles Of Acetyl Coa
Thus Atp From 7 Cycles = 7× 4 Atp (New) & 5 Atp (Old)= 28 Atp (New) & 35 Atp (Old)
And Atp From 8 Acetyl Coa Via Tca Cycle= 8× 10 Atp (New) & 12 Atp (Old)= 80 Atp (New) & 96 Atp (Old)
★★★finally Net Atp From 1 Palmitic Acid=
28 Atp (New) & 35 Atp (Old) + 80 Atp (New) & 96 Atp (Old) - 2atp (For Initial Activation)= 106 Atp (New) & 129 Atp (Old) ★★★
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